Question 464941
4 men, 6 women
.
i) 
6C4/10C4
=15/210
=1/14 probability of 4 w.
.
ii)
(6C3 * 4C1)=8/21 Probability of 3 w and 1 m.
1-(1/14 + 8/21)=
1 - 19/42
23/42 Probability at least two will be men.
.
Ed