Question 464951
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi, Inanswer to Your question:  Yes, f(x) maximum value is the 6.
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x) = -4(x+3)^2+6 | {{{highlight(V(-3,6))}}}, a = -4<0, parabola opens downward, vertex a max Pt
x = -3, line of symmetry
{{{drawing(300,300,   -10,10,-10,10, blue(line(-3,10,-3,-10))    grid(1),
circle(-3, 6,0.4),
graph( 300, 300, -10,10,-10,10,0, -4(x+3)^2+6))}}}