Question 464752
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y = x^2 + 6x - 1  |Completing square to put into vertex form
y = (x+3)^2 - 9 - 1
y = (x+3)^2 - 10   |Note vertex is Pt(-3,-10) a = 1 >0 parabola opens upward
{{{drawing(300,300, -10, 10, -10, 10,  grid(1),
circle(-3, -10,0.4),
graph( 300, 300,  -10, 10, -10, 10,0,x^2+6x-1))}}}