Question 464938
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x) = -x^2 + 6  |Vertex(0,{{{highlight(6)}}}) Maximum PT, parabola opens downward: a = -1 < 0
Line of symmetry is the y-axis
{{{drawing(300,300, -10, 10, -10, 10,  grid(1),
circle(0,6,.4),
graph( 300, 300,  -10, 10, -10, 10,0,-x^2 + 6))}}}