Question 464935
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I'm going to presume that you have a roof that inclines at a 9.5 degree angle from the horizontal and that you have a skylight/frame that will mount into a hole in the roof such that the dimension of the skylight along the surface of the roof from the low end of the skylight to the high end of the skylight is 10 feet.  And finally, I am going to presume that the dimension you seek is the vertical displacement between the high and low ends of the skylight.


Under the presumptive conditions, the dimension you need divided by the dimension you know, namely 10 feet, is equal to the sine of 9.5 degrees.  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 10\sin9.5^\circ]


Roughly, 1.65 feet, or a thumbnail more than 1 foot *[tex \Large 7\frac{3}{4}\ \ ]inches



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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