Question 464880
x squared-9 over x+2 then all that over x-3 over x-2
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[(x^2-9)/(x+2)]/[(x-3)/(x-2)]
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= [(x^2-9)/(x+2)]*[(x-2)/(x-3)]
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= [(x+3)(x-2)]/(x+2)
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Cheers,
Stan H.
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