Question 464665
If it's supposed to be written this way:

{{{3^(log(3,(6x-4)))}}}, 

then the answer is simply

6x-4.

This answer springs from the fact that the logarithmic function {{{f(x) = a^x}}} has inverse function {{{f^(-1)(x) = log(a, x)}}}.  Then from algebra we know that

{{{x = f(f^(-1)(x)) = a^log(a,x)}}}.

(Notes: 1) a > 0 and {{{a<>1}}}
2) Both functions {{{f(x) = a^x}}} and {{{f^(-1)(x) = log(a, x)}}} are 1-to-1, and hence have inverses.)