Question 464519
The time T for a pendulum to swing back and forth once is called its period and is given by 
T = 2π √ L/g 
where L equals the length of the pendulum. The table lists the periods of pendulums with different lengths. 
L(feet)............. 0.5...........1.0..........1.5 
T(seconds)..... 0.78.........1.11........1.36 
(a) Solve the formula for g.
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 T = 2π √ L/g 
sqrt(L/g) = T/(2pi)
L/g = [T/(2pi)]^2
g = L/[T/(2pi)]^2
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(b) Use the table to determine the value of g. (Note: The 
units for g are feet per second) 

Using the point (1,1.11), solve for "g":
g = 1.11/[1/(2pi)]^2
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g = 1.11*4(pi^2)
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g = 43.821 ft/sec
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(c) Interpret the result.
The force of gravity on the pendulum is 43.821 ft.sec
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Cheers,
Stan H.