Question 464407
Yes, that's correct. However there are two solutions for x, not just one.


When you have *[tex \LARGE x^2 = 160], taking the square root of both sides will result in *[tex \LARGE x = 4\sqrt{10}].  However, x can also be equal to *[tex -4\sqrt{10}] (the negative solution). This is a common place to mess up. For square roots it is pretty easy to compensate; just put a +/- sign in front. When you have cube or fourth roots and you want to find all such roots you will have to use complex numbers.