Question 464461
-3,-2,-1 works as well. But then {-1,0,1}, {1,2,3} and {-3,-2,-1} are the only sets of three consecutive integers satisfying this property, because if we were to write it algebraically (e.g. (a-1) + a + (a+1) = (a-1)a(a+1), 3a = a(a-1)(a+1)) we would get a cubic, which has at most three distinct solutions for a.