Question 464305
Assuming
{{{4y^2 +16y + 16 = 0}}}
.
Divide both sides by 4.
{{{y^2 +4y + 4 = 0}}}
.
What the factors of 4?
{{{2 * 2}}}
What is the sum of the factor?
{{{2 + 2}}}
.
So, that tells us the factors are:
.
{{{(y+2)(y+2) = y^2 +2y +2y + 4}}}
.
Collecting terms
{{{y^2 +2y +2y + 4 = y^2 +4y + 4}}
.
This also can be shown as:
{{{(y+2)^2 = 0}}}
.
Either way, we see  there is one root:  y=-2