Question 464251
<pre>
{{{(2x^2y^(-1))^(-6)}}}

Give the 2 an exponent of 1 so that everything
inside the parentheses has an exponent showing:

{{{(2^1x^2y^(-1))^(-6)}}}

Remove the parentheses by multiplying every
exponent inside the parentheses, the 1, the 2, and the -1 
by the exponent -6 just outside the parentheses. When
you do that you have:

{{{2^(-6)x^(-12)y^6}}}

Put that over 1:

{{{(2^(-6)x^(-12)y^6)/1}}}

Now to get rid of a negative exponent in the
top (bottom) of a fraction, move the base and exponent
to the bottom (top) and change the sign of the
exponent to positive:

Bring the {{{2^(-6)}}} to the bottom as {{{2^6}}}
Bring the {{{x^(-12)}}} to the bottom as {{{x^12}}}
But leave the {{{y^6}}} in the top because it already
has a positive exponent.

{{{(y^6)/(2^6x^12)}}}

One more thing {{{2^6=2*2*2*2*2*2 = 64}}}

So the final answer is:

{{{(y^6)/(64x^12)}}}

Edwin</pre>