Question 464227
x+b/2y=-b^2/4
x-y=-1      where b does not equal to -2

I changed x-y=-1 to y=1+x

then;  x+b/2(1+x)=-b^2/4
x + b = (-b^2/4)*2(1+x) = -b^2/2 - b^2x/2
x + b^2x/2 = -b - b^2/2
x(1 + b^2/2) = -b - b^2/2
{{{x = -(b + b^2/2)/(1 + b^2/2)}}}
{{{x = -(2b + b^2)/(2 + b^2)}}}

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y = x+1
{{{y = (-2b - b^2 + 2 + b^2)/(2 + b^2)}}}
{{{y = (-2b + 2)/(2 + b^2)}}}