Question 1063
First, look at the general vertex form of parabola
:
y = (x-h)^2+k
:
where h is the location of the point on x-axis and k is the location of the point of the y-axis. So in your equation, y = (x-4)^2+5, the vertex is gonna be (4,5). Let me show u the graph...
:
{{{graph(200,400,-20,20,-100,100,(x-4)^2+5)}}}