Question 463937

2-r/7-r  = 5/r-7

=> (2-r)/(7-r) - 5/(r-7) = 0

=> (2-r)/(7-r) + 5/(7-r) = 0

=> [2-r +5]/(7-r) = 0

=> (7-r)/(7-r) = 0 


r = 7