Question 463882
What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 39 ?
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a(6) = 4 + 5d = 39
5d = 35
d = 7
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a(32) = 4 + (32-1)7
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a(32) = 4 + 31*7
a(32) = 221
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Cheers,
Stan H.
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