Question 47981
Factor:
{{{8x^3-1}}} You should recognise this as the difference of two cubes {{{(2x)^3-(1)^3}}}
The difference of two cubes can be factored thus:
{{{A^3-B^3 = (A-B)(A^2+AB+B^2)}}} Applying this to your problem in which A = 2x and B = 1:
{{{(2x)^3-(1)^3 = (2x-1)(4x^2+2x+1)}}}...and this is as far as you can go with this.