Question 463378
8x^6 + 27


It is a "sum of two cubes", in the form a³ + b³.
It factors into the form (a + b)(a² - ab + b²)


If a³ is 8x^6, then a is 2x² {the cube root of 8x^6}
If b³ is 27, then b is 3 {the cube root of 27}


So, substitute 2x² in for a, and 3 in for b, into:
(a + b)(a² - ab + b²)


= (2x^2 + 3)(4x^4 - 6x^2 + 9) 
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