Question 463323


The perimeter of a rectangle is {{{P=60 m}}}. 

If its length {{{L}}} is twice its width {{{W}}}, then its area {{{A}}} is:


{{{A=L*W}}}....since {{{L=2W}}} area will be

{{{A=2W*W}}}

{{{A=2W^2}}}.......now use {{{P}}} to find {{{W}}} 

{{{P=2(L+W)}}}

{{{60 m=2(2W+W)}}}

{{{cross(60)30 m=cross(2)(2W+W)}}}

{{{30 m=3W}}}

{{{30 m/3=W}}}

{{{10 m=W}}}

now find {{{L}}}

{{{L=2W}}}...->...{{{L=20m}}}


{{{A=2W^2}}}

{{{A=2*(10m)^2}}}

{{{A=2(100m^2)}}}

{{{A=200m^2}}}

or

{{{A=L*W}}}

{{{A=20m*10m}}}

{{{A=200m^2}}}