Question 47996
[sqrt(3) +2)]/ [sqrt(7) - 7] 

Multiply numerator and denominator by sqrt(7)+7 to get:

[sqrt3+2][[sqrt7+7]/[sqrt7-7][sqrt7+7]

= [sqrt21+7sqrt3 + 2sqrt7 +14]/(7-49)
= [sqrt21+7sqrt3 + 2sqrt7 +14]/(-42)

The negative could be distributed throughout the numerator.

Cheers,
Stan H.