Question 47943
find the x intercepts
{{{y=x^2+2x-8}}}
First in order to slove for x we have to set y equal to zero.
{{{0=x^2+2x-8}}}
Now you have to factor.
{{{0=x^2+2x-8}}}
     (x+4)(x-2)
Now set x eqaul to zero and solve for x
Answer :
x=-4
x=2