Question 462805

{{{x + 3y = 7}}}..........1

{{{4x-5y = 96}}}..........2
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{{{x + 3y = 7}}}..........1..solve for {{{x}}}

{{{x =- 3y+ 7}}}.......substitute in 2

{{{4(3y+ 7)-5y = 96}}}.....solve for {{{y}}}

{{{12y+ 28-5y = 96}}}

{{{7y= 96-28}}}

{{{7y= 68}}}

{{{y= 68/7}}}

{{{y= 9.72}}}

now find {{{x}}}

{{{x =- 3( 9.72)+ 7}}}

{{{x =-29.16+ 7}}}

{{{x =-22.16}}}

so, {{{x =-22.16}}} and {{{y= 9.72}}}
 

check:


{{{x + 3y = 7}}}

{{{-22.16 + 3(9.72) = 7}}}

{{{-22.16 + 29.16 = 7}}}

{{{7 = 7}}}