Question 462416
The discriminant is b² - 4ac


If b² - 4ac = 0, there is one real number solution
If b² - 4ac < 0, there are two imaginary number solutions
If b² - 4ac > 0, there are two real number solutions


10x² - 4x - 7 = 0
a = 10, b = -4, and c = -7


b² - 4ac 
= (-4)² - 4(10)(-7) {substituted values into the discriminant}
= 16 + 280 {multiplied}
= 296 {added}


296 > 0, there are two real number solutions
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