Question 47846
solve for x.
{{{sqrt(3x+10)=5-2x}}}

first we have to get rid of the sq root sign so you square it.

{{{(sqrt(3x+10))^2=5-2x}}}
which cancels the sqrt and leaves us with

{{{3x+10=5-2x}}}
now put like terms togeather
{{{5x=-5}}}
now divide by 5
{{{x=-5/5}}}
answer: x=-1