Question 462224
x = sum of money

t = number of months

interest rate = {{{0.07/12}}}


{{{2x = x*(1+(0.07/12))^t}}} Divide both sides by x to give

{{{2 = (1+(0.07/12))^t}}} take logs of both sides

{{{log 2 = t*log (1+(0.07/12))}}}

{{{log 2/(log(1+(0.07/12))) = t}}}

{{{t=119.17}}} so about 119 months which is nearly 10 years.