Question 461983
consultant traveled in a car for 3 hours to attend a meeting.
 The return trip took only 2 hours (different route) because his speed was 8 miles per hour faster.
 The total trip was 291 miles. What was the consultant's speed each way?
:
Let s = speed to the meeting
then
(s+8) = return speed
:
Write a distance equation, dist = time * speed
:
3s + 2(s+8) = 291
3s + 2s + 16 = 291
5s = 291 - 16
5s = 275
s = {{{275/5}}}
s = 55 mph to the meeting
and
55 + 8 = 63 mph from the meeting
:
:
Check solutions by finding the actual dist of each trip
3(55) + 2(63) = 
165 + 126 = 291, confirms our solutions