Question 462118
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There are two ways to go about this.


You can just use FOIL in the normal way.  First, Outside, Inside, Last, then sum and collect like terms, or...


...you can just recognize that this is the product of two binomial conjugates so the product is the difference of two squares, thus:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (a\ +\ b)(a\ -\ b)\ =\ a^2\ -\ b^2]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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