Question 462032
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{8}{w\ +\ 8}\ =\ \frac{5}{3w}]


Or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{8}{w\ +\ 8}\ =\ \frac{5}{3}w]


If it is the first way, your LCD is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3w(w\ +\ 8)\ =\ 3w^2\ +\ 24w]


If it is the second way, your LCD is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3(w\ +\ 8)\ =\ 3w\ +\ 24]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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