Question 461926
find loga[(x^2) (z^3)/ (sqrt (y)))
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= loga(x^2) + loga(z^3) - loga(sqrt(y))
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= 2loga(x) + 3loga(z) - (1/2)loga(y)
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where loga(x)=2, loga(y)=6, and loga(z)=-2
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substitute to get:
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= 2*2 + 3(-2) - (1/2)6
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= 4 - 6 - 3
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= -5
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Cheers,
Stan H.
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