Question 461707

{{{(7x-49)/(7-x)}}}

={{{(7x-7*7)/(7-x)}}}

={{{7(x-7)/(7-x)}}}....take {{{minus}}} out of parentheses in nominator {{{7(x-7)}}}:{{{-7(-x+7)}}}  or {{{-7(7-x)}}}

={{{-7(7-x)/(7-x)}}}...simplify

={{{-7cross((7-x))/cross((7-x))}}}

={{{-7}}}