Question 47857
This will look like a hyperbola.
Standard Form: {{{(x - h)^2/a^2 - (y - k)^2/b^2 = 1}}}
Centre(h,k)
C(0,0)
a = 4
b = 2
This hyperbola is horizontal because the {{{x}}} value is over the {{{a}}} value.
Asymptote: {{{y - y1 = M(x - x1)}}} where {{{M}}} = +-{{{b/a}}}
Asymptote: {{{y}}} = +-{{{(1/2)x}}}
{{{graph(600,600,-20,20,-20,20,sqrt(-4 + (x^2)/4),-sqrt(-4 + (x^2)/4),x/2,-x/2)}}}