Question 47865
y = 3x^2 - 6x - 4
v(-b/2a,f(x))
Since the parabola is vertical, the Axis of Symmetry is: {{{x = -b/2a}}}
{{{x = 1}}}
Since the value of {{{a}}} is positive, the parabola opens upwards. The vertex is a minimum.
{{{graph(600,600,-10,10,-10,10,3x^2-6x-4)}}}