Question 461491


easiest way is to find {{{x}}} or {{{y-intercept}}}

set {{{x}}} to zero, and find {{{y-intercept}}}

{{{x-3y=6 }}}

{{{0-3y=6 }}}

{{{-3y=6 }}}

{{{y=6/-3 }}}

{{{y=-2 }}}

so, the point (0,-2) lies on the line whose equation {{{x-3y=6 }}}

here is the graph:


{{{x-3y=6 }}}.....i {{{slope-intercept form}}}: {{{(1/3)x-2=y }}}

{{{ graph( 500, 500, -10,10, -10, 10, (1/3)x-2) }}}