Question 461279


{{{y=x^2-6x+5}}}.....set {{{y=0}}} to find {{{x-intercept}}}


{{{0=x^2-6x+5}}}....use quadratic formula

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

{{{x = (-(-6) +- sqrt( (-6)^2-4*1*5 ))/(2*1) }}} 

{{{x = (6 +- sqrt( 36-20 ))/2 }}} 

{{{x = (6 +- sqrt( 16 ))/2 }}} 

{{{x = (6 +- 4)/2 }}} 

{{{x = (6 + 4)/2 }}} 

{{{x = 10/2 }}}

{{{x = 5 }}}....first {{{x-intercept}}}


{{{x = (6 -4)/2 }}} 

{{{x = 2/2 }}}

{{{x = 1 }}}......second {{{x-intercept}}}


now, set {{{x=0}}} and find {{{y-intercept}}}


{{{y=0^2-6*0+5}}}

{{{y=5}}}..........{{{y-intercept}}}


let's see it on a graph:

{{{ graph( 500, 500, -10, 10, -10, 10,x^2-6x+5) }}}