Question 47836
SEE THE FOLLOWING EXAMPLE AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK
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Y INTERCEPT IS DETERMINED BY THE POINTS WHERE THE CURVE INTERSECTS X AXIS.HENCE THIS IS
OBTAINED BY EQUATING THE EQN. TO ZERO AND FINDING VALUES OF X SATISFYING THE EQN.
What is the y-intercept of the function, y=f(x)=2x^2+4x-6?=0
x^2+2x-3=0
x^2+3x-x-3=0
x(x+3)-1(x+3)=0
(x+3)(x-1)=0
x=-3 and x=1 ARE THE 2 Y INTERCEPTS. 
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i need help with this quadratic using the formula.. i did the work and my answer came out to be irrational is this true?
a=3x^2+
b=8x+
c=2
3x^2+8x+2=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-8 +- sqrt( 8^2-4*3*2 ))/(2*3) }}}
{{{x = (-8 +- sqrt( 64-24 ))/(6) }}}
{{{x = (-8 +- 2*sqrt(10))/(6) }}}
{{{x = (-4 +- sqrt(10))/(3) }}}
yes you are correct.the roots are irrational