Question 461257


{{{x^2+3jx-2=0}}}

{{{a=1}}}, {{{b=3j}}}, and {{{c=-2}}}

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

{{{x = (-3j +- sqrt( (3j)^2-4*1*(-2) ))/(2*1) }}}

{{{x = (-3j +- sqrt( 9j^2+8 ))/2 }}}

{{{x = (-3j/2) +- sqrt( 9j^2+8 )/2 }}}