Question 459119
how do you graph x=y^2-6y+6
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x=y^2-6y+6
x=(y^2-6y+9)+6-9
x=(y-3)^2-3
Equation is a parabola with vertex at (-3,3). It opens rightward and has an axis of symmetry at y=3
See graph below as a visual check on the answers.
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y=(x+3)^.5+3

{{{ graph( 300, 300, -10, 10, -10, 10,(x+3)^.5+3,-(x+3)^.5+3) }}}