Question 460728
A bag contains 20 batteries, of which six are defective. Selecting two at random, without replacement, determine the probability that none of the batteries you select are good.
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# of ways to select 2 defective batteries: 6C2 = 15
# of ways to select 2 batteries from 20: 20C2 = 190
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P(select 2 defective) = 15/190 = 3/38
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Cheers,
Stan H.
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>3/5
>3/10
>3/38
>9/100