Question 460728
P(2 Defective) = P(Defective AND defective)



P(2 Defective) = P(Defective) * P(Defective)



P(2 Defective) = (6/20)*(5/19)



P(2 Defective) = (6*5)/(20*19)



P(2 Defective) = 30/380



P(2 Defective) = 3/38



So the probability that both are defective is 3/38, which means that the answer is choice C)