<PRE><B>Question 47791</B>
x^2+y^2-6x-4y+13=36
Complete the square on the x terms and on the y terms separately to get:

x^2-6x+9 +y^2-4y+4 =36-13+9+4

(x-3)^2 + (y-2)^2 = 36

This is the equation for a circle with center
at (3,2) and radius of 6

Cheers,
Stan H.

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