Question 47789
a=3x^2+
b=8x+
c=2
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The a,b,and c are the coefficients of the terms,
not the terms themselves.
a=3
b=8
c=2
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Then the determinant is b^2-4ac = 64-4*3*2=40
Since this is greater than zero the quadratic has
two real zeroes. The zeroes may be irrational and
still be real.
Consider the following:
*[invoke quadratic "x",3,8,2]
Hope this helps.
Cheers,
Stan H.