Question 460431
Let x ml - 2% alcohol
Let y ml - 10% alcohol
Then {{{x+y=2000}}}
In x ml 2% solution is {{{0.02x}}}ml of alcohol, in y ml 10% solution is {{{0.1y}}}ml of alcohol, in 2000 ml 6% solution is {{{0.06*2000=120}}}ml of alcohol, so {{{0.02x+0.1y=120}}}
The system of equations
{{{system(x+y=2000,0.02x+0.1y=120)}}}
{{{system(y=2000-x,0.02x+0.1(2000-x)=120)}}}
{{{system(y=2000-x,0.02x+200-0.1x=120)}}}
{{{system(y=2000-x,-0.08x=-80)}}}
{{{system(y=2000-x,x=(-80)/(-0.08))}}}
{{{system(x=1000,y=2000-1000)}}}
{{{system(x=1000,y=1000)}}}
x=1000 ml - 2% alcohol, y=1000 ml - 10% alcohol
.
Check
{{{system(1000+1000=2000,0.02*1000+0.1*1000=120)}}}
{{{system(2000=2000,120=120)}}}