Question 460151
let a be the amount invested in the account at 8%
let b be the amount invested in the account at 10%
let c be the amount invested in the account at 11%

We know that a = 2b and c= 3b

So if express all three account in terms of b we get (2b*8%)+(b*10%)+(3b*11%) = $472

(16b/100)+(10b/100)+(33b/100) = $472

59b/100 = $472

59b = $47200

b = $800

a = 2b = 2*800 = $1600
c = 3b = 3*800 = $2400