Question 460102
From {{{8x^2+7x+3}}} we can see that {{{a=8}}}, {{{b=7}}}, and {{{c=3}}}



{{{D=b^2-4ac}}} Start with the discriminant formula.



{{{D=(7)^2-4(8)(3)}}} Plug in {{{a=8}}}, {{{b=7}}}, and {{{c=3}}}



{{{D=49-4(8)(3)}}} Square {{{7}}} to get {{{49}}}



{{{D=49-96}}} Multiply {{{4(8)(3)}}} to get {{{(32)(3)=96}}}



{{{D=-47}}} Subtract {{{96}}} from {{{49}}} to get {{{-47}}}



So the discriminant is {{{D=-47}}}



Since the discriminant is less than zero, this means that there are two complex solutions.



In other words, there are no real solutions.