Question 460076
One car		9m			
another car	22m			
distance between them	x m			
By Pythagoras theorem 								
Hypotenuse^2 = Leg1^2+leg2^2								
{{{ x^2	=9^2+22	^2}}}
x ^2=81+484			
x ^2=565					
{{{ sqrt(x^2)=sqrt(565)}}}				
x= 23.77 m