Question 460048
given: slope {{{m=-1/7}}} and point (x1, y1)=(-7, 5)

{{{y=mx+-b}}}.........{{{slope-intercept}}} form

if you are given one point:


{{{y=mx+(y1-mx1)}}}

{{{y=-(1/7)x+(5-(-1/7)(-7))}}}

{{{y=-(1/7)x+(5-(7/7))}}}

{{{y=-(1/7)x+(5-1)}}}


{{{y=-(1/7)x+4}}}

{{{ graph( 500, 500, -15,20, -10, 15,-(1/7)x+4) }}}