Question 459876
assume the problem is:
{{{10/4}}}y + {{{6/2}}}= 2y - 2
the common denominator would be 4, multiply each term by 4
4*{{{10/4}}}y + 4*{{{6/2}}}= 4(2y) - 4(2)
Cancel the denominators and you have
10y + 2(6) = 8y - 8
10y + 12 = 8y - 8
10y - 8y = -8 - 12
2y = -20
y = {{{(-20)/2}}}
y = -10
:
:
See if that checks out, replace y with -10 in the original problem
{{{10/4}}}(-10) + {{{6/2}}}= 2(-10) - 2
{{{-100)/4}}} + 3 = -20 - 2
-25 + 3 = -22