Question 5994
So I take it you're stuck at {{{ 4 = ((x-6)(x-4))/x }}}.


All you'll do is cross-multiply. It might be easier if we put it this way:


{{{ 4/1 = ((x-6)(x-4))/x }}}


Then we'll get {{{ 4x = (x-6)(x-4) }}}


{{{ (x-6)(x-4) - 4x = 0 }}} <----- We switched the places of the expressions on both sides of the equals sign, and then moved the 4x to the other side so that everything equals zero.


{{{ x^2 - 10x + 24 - 4x = 0 }}} <----- We expanded by using the product by using FOIL.


{{{ x^2 -14x + 24 = 0 }}} <--- Combined like terms


{{{ (x - 12)(x - 2) = 0 }}} <---- Refactored ("UnFoiled")


From looking at your above equation, x = 12 or x = 2.