Question 459569
f(x)=(x+3)(x-5)/(x+1)(x-4) find the domain and range
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f(x)=(x+3)(x-5)/(x+1)(x-4)
To find domain, set denominator=0, solve for x
(x+1)(x-4)=0
x+1=0
x≠-1
x-4=0
x≠4
Domain: (-∞,1) U (1,4) U (4,∞)
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To find range interchange x & y, then solve for y
x=(y+3)(y-5)/(y+1)(y-4)

Range: (-∞,∞)