Question 459945
Solve
:
{{{8/((y+2))}}} = {{{7/((y-9))}}}
:
When you have single a fractions on each side of the equal side, you can cross multiply:
8(y-9) = 7(y+2)
:
8y - 72 = 7y + 14
:
8y - 7y = 14 + 72
:
y = 86
:
:
Check this in the original equation
{{{8/((86+2))}}} = {{{7/((86-9))}}}
{{{8/88}}} = {{{7/77}}}
:
How about this, is this stuff making sense to you now? 
Just knowing a few rules makes it possible to solve a lot of these problems.